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-3.05+17.2x-4.9x^2=0
a = -4.9; b = 17.2; c = -3.05;
Δ = b2-4ac
Δ = 17.22-4·(-4.9)·(-3.05)
Δ = 236.06
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17.2)-\sqrt{236.06}}{2*-4.9}=\frac{-17.2-\sqrt{236.06}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17.2)+\sqrt{236.06}}{2*-4.9}=\frac{-17.2+\sqrt{236.06}}{-9.8} $
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